an integer array of 15 elements is declared in a c program. the memory location of the first byte of the array is 2000. what will be the location of the 13th element of the array? assume int takes 2 bytes of memory.

The location of the 13th element will be 2024.

Step-by-step reasoning

• The array has 15 int elements, and each int takes 2 bytes.

• The base address (first byte of the first element) is 2000.

• In C, arrays are 0-indexed , so:
  • 1st element → index 0
  • 13th element → index 12.

Now use the address formula:

Address of element at index iii
= base address + i×i\times i× size of each element.

So for the 13th element (index 12):

• Offset = 12×2=2412\times 2=2412×2=24 bytes.

• Address = 2000+24=20242000+24=20242000+24=2024.

Answer: 2024 TL;DR:
13th element is at index 12, each int is 2 bytes, so 2000+12×2=20242000+12\times 2=20242000+12×2=2024.

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