gold has a density of 19,300 kg/m³. calculate the mass of 0.02 m³ of gold in kilograms.

Gold has a density of 19,300 kg/m³, so the mass of 0.02 m³ is calculated using the formula mass = density × volume. This yields 19,300 kg/m³ × 0.02 m³ = 386 kg.
Calculation Breakdown
Density (ρ\rho ρ) equals mass (mmm) divided by volume (VVV), rearranged as m=ρ×Vm=\rho \times Vm=ρ×V.
Plugging in values: m=19,300×0.02=386m=19{,}300\times 0.02=386m=19,300×0.02=386 kg.
This matches standard references confirming gold's density at exactly 19,300 kg/m³.
Quick Facts on Gold Density
- 19.3 g/cm³ converts to 19,300 kg/m³ (multiply by 1,000).
- Among the densest metals, heavier than lead (11,340 kg/m³) or iron (~7,870 kg/m³).
- Pure 24-karat gold; alloys are less dense.
TL;DR: 386 kg.
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