There are approximately 6.52×10226.52\times 10^{22}6.52×1022 atoms in 4.33 grams of argon.

Step-by-step idea

  • Argon’s molar mass is about 39.95 grams per mole.
  • One mole of any element contains Avogadro’s number of atoms, which is about 6.022×10236.022\times 10^{23}6.022×1023 atoms per mole.

1. Convert grams to moles

moles of Ar=4.33textg39.95textg/mol≈0.108textmol\text{moles of Ar}=\frac{4.33\\text{g}}{39.95\\text{g/mol}}\approx 0.108\\text{mol}moles of Ar=39.95textg/mol4.33textg​≈0.108textmol

2. Convert moles to atoms

atoms of Ar=0.108textmol×6.022×1023textatoms/mol≈6.52×1022textatoms\text{atoms of Ar}=0.108\\text{mol}\times 6.022\times 10^{23}\\text{atoms/mol}\approx 6.52\times 10^{22}\\text{atoms}atoms of Ar=0.108textmol×6.022×1023textatoms/mol≈6.52×1022textatoms

So, 4.33 grams of Ar contains about 6.5×10226.5\times 10^{22}6.5×1022 atoms.