how many bits would you need if you wanted to count up to the decimal number 1000?
You would need 10 bits to count up to the decimal number 1000.
Quick Scoop: Why 10 Bits?
Think of bits as tiny switches that can be 0 or 1.
With nnn bits, you can represent numbers from 0 up to 2nβ12^n-12nβ1. We want
to be able to count up to 1000 , so we need the smallest nnn such that:
2nβ1β₯10002^n-1\ge 10002nβ1β₯1000
Letβs check nearby powers of 2:
- 29=5122^9=51229=512 β can count only up to 511 (not enough).
- 210=10242^{10}=1024210=1024 β can count up to 1023, which covers 1000.
So 9 bits are too few, but 10 bits are enough, meaning you need 10 bits to count up to (and include) 1000.
A Tiny Story Version
Imagine a digital odometer with little windows that show only 0s and 1s instead of digits 0β9.
- With 9 windows (bits), the biggest pattern you can show is 111111111, which corresponds to 511 in decimal.
- You try to display 1000, but you run out of patterns.
- You add one more window, making it 10 bits.
Now your maximum pattern is 1111111111, which corresponds to 1023 β plenty of room to include 1000.
So, once that 10th bit is added, your counter can happily go all the way up to 1000.
TL;DR
To have the ability to count from 0 up to the decimal number 1000, you need 10 bits.
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