how many liters of oil at rs.40 per liter should be mixed with 240 liters of a second variety of oil at rs.60 per liter so as to get a mixture whose cost is rs.52 per liter?

June 27, 2026 • 1 min read

Let the required quantity of the first oil (at Rs.40 per liter) be xxx liters. We have:

First oil: xxx liters at Rs.40 per liter
Second oil: 240 liters at Rs.60 per liter
Mixture: (x+240)(x+240)(x+240) liters at Rs.52 per liter

Total cost of mixture = cost of first oil + cost of second oil:

40x+60⋅240=52(x+240)40x+60\cdot 240=52(x+240)40x+60⋅240=52(x+240)

40x+14400=52x+1248040x+14400=52x+1248040x+14400=52x+12480

Bring like terms together:

14400−12480=52x−40x14400-12480=52x-40x14400−12480=52x−40x

1920=12x1920=12x1920=12x

x=192012=160x=\frac{1920}{12}=160x=121920=160

So, 160 liters of oil at Rs.40 per liter should be mixed with the 240 liters of oil at Rs.60 per liter.

Kaliyugavaradhan

Written by Kaliyugavaradhan

"Reading nourishes the soul like no other activity." — This philosophy guides my writing and exploration of ideas.