how many moles of naoh will react with 38 moles of h2so4?

38 moles of H₂SO₄ will react with 76 moles of NaOH.

Step-by-step explanation

1. Balanced equation for the reaction:
   2 NaOH+H2SO4→Na2SO4+2 H2O2\text{ NaOH}+\text{H}_2\text{SO}_4\rightarrow \text{Na}_2\text{SO}_4+2\text{ H}_2\text{O}2 NaOH+H2​SO4​→Na2​SO4​+2 H2​O.

2. From the balanced equation, the mole ratio is:
   • 2 moles NaOH : 1 mole H₂SO₄.

3. For 38 moles of H₂SO₄:
   • Moles of NaOH needed
     =38×2 mol NaOH1 mol H2SO4=76 mol NaOH=38\times \frac{2\text{ mol NaOH}}{1\text{ mol H}_2\text{SO}_4}=76\text{ mol NaOH}=38×1 mol H2​SO4​2 mol NaOH​=76 mol NaOH.

So, 76 moles of NaOH are required to react completely with 38 moles of H₂SO₄.