For a mine winch, the distance the counterweight moves in one full rotation of the drum is equal to the circumference of the drum.

Step-by-step

  • Given drum diameter D=6D=6D=6 m.
  • Circumference of a circle is C=πDC=\pi DC=πD (or equivalently C=2πrC=2\pi rC=2πr).
  • Substitute D=6D=6D=6 m:
    C=π×6≈3.14159×6≈18.85C=\pi \times 6\approx 3.14159\times 6\approx 18.85C=π×6≈3.14159×6≈18.85 m.

So, the counterweight will move (lift) approximately 18.85 m for each single rotation of a 6 m diameter winch drum, assuming no slip of the cable.

TL;DR: If the mine winch drum diameter is 6 m, the counterweight will move about 18.85 m per rotation.

Information gathered from public forums or data available on the internet and portrayed here.