two jackets were bought at the same cost. one was sold at a profit of 9 % and the other at a profit of 15 % . if the difference in the selling price of both the jackets was ₹ 105 , then what was the cost price of each jacket?

The cost price of each jacket is ₹1750.

Step-by-step solution

Let the cost price of each jacket be CPCPCP.

1. Write selling prices using profit percentages

• First jacket: sold at a profit of 9%
  Selling price SP1=CP+9% of CP=1.09×CPSP_1=CP+9%\text{ of }CP=1.09\times CPSP1​=CP+9% of CP=1.09×CP.

• Second jacket: sold at a profit of 15%
  Selling price SP2=CP+15% of CP=1.15×CPSP_2=CP+15%\text{ of }CP=1.15\times CPSP2​=CP+15% of CP=1.15×CP.

2. Use the given difference in selling prices

The difference in their selling prices is ₹105:

SP2−SP1=105SP_2-SP_1=105SP2​−SP1​=105

1.15CP−1.09CP=1051.15CP-1.09CP=1051.15CP−1.09CP=105

0.06CP=1050.06CP=1050.06CP=105

3. Solve for CP

CP=1050.06=1750CP=\frac{105}{0.06}=1750CP=0.06105​=1750

So, the cost price of each jacket = ₹1750.

Answer: Each jacket was bought for ₹1750. ✅

TL;DR: Difference of 6% profit on the same cost equals ₹105, so 6% of CP is 105 → CP = 105 ÷ 0.06 = 1750.