two squares are chosen at random on a chessboard. what is the probability that they have a side in common?
The probability is 19\displaystyle \frac{1}{9}91.
Step-by-step reasoning
A standard chessboard has 8×8=648\times 8=648×8=64 squares.
- Total ways to choose 2 squares
Any 2 distinct squares can be chosen in
(642)=64×632=2016\binom{64}{2}=\frac{64\times 63}{2}=2016(264)=264×63=2016
ways.
- Count pairs of squares sharing a side
Classify squares by how many neighbors (sharing a side) they have:
- Corner squares: 4 corners, each has 2 neighbors → 4×2=84\times 2=84×2=8 neighbor-relations.
- Edge (non-corner) squares:
- Each edge has 6 such squares, and there are 4 edges → 4×6=244\times 6=244×6=24 squares.
- Each has 3 neighbors → 24×3=7224\times 3=7224×3=72 neighbor-relations.
- Interior squares:
- Remaining squares: 64−4−24=3664-4-24=3664−4−24=36.
- Each has 4 neighbors → 36×4=14436\times 4=14436×4=144 neighbor-relations.
Total “square–neighbor” relations:
8+72+144=224.8+72+144=224.8+72+144=224.
But each pair of adjacent squares is counted twice in that total (once from each square’s perspective), so the actual number of unordered adjacent pairs is:
2242=112.\frac{224}{2}=112.2224=112.
- Compute the probability
P(share a side)=favorable pairstotal pairs=1122016=118×2=19.P(\text{share a side})=\frac{\text{favorable pairs}}{\text{total pairs}} =\frac{112}{2016}=\frac{1}{18}\times 2=\frac{1}{9}.P(share a side)=total pairsfavorable pairs=2016112=181×2=91.
So, when two squares are chosen at random on a chessboard, the probability that they share a common side is 19\boxed{\frac{1}{9}}91.