what is the derivative of ln
The derivative of the natural logarithm is:
ddx[ln(x)]=1x,x>0.\frac{d}{dx}[\ln(x)]=\frac{1}{x},\quad x>0.dxd[ln(x)]=x1,x>0.
Quick Scoop
Think of ln(x)\ln(x)ln(x) as a smooth curve that grows slowly as xxx increases. Its slope at any point xxx is exactly 1/x1/x1/x:
- At x=1x=1x=1, the slope is 111.
- At x=2x=2x=2, the slope is 1/21/21/2.
- As xxx gets larger, the slope gets smaller, matching the idea that ln(x)\ln(x)ln(x) grows more and more slowly.
If you meant a more complicated function like ln(g(x))\ln(g(x))ln(g(x)), then by the chain rule,
ddx[ln(g(x))]=g′(x)g(x).\frac{d}{dx}[\ln(g(x))]=\frac{g'(x)}{g(x)}.dxd[ln(g(x))]=g(x)g′(x).
You can use this pattern for things like ln(x2+1)\ln(x^2+1)ln(x2+1), ln(3x)\ln(3x)ln(3x), or ln(lnx)\ln(\ln x)ln(lnx).