The potential difference between the two points is 7 V. Using the relation between work, charge, and potential difference:

V=WqV=\frac{W}{q}V=qW​

Here, work W=14 JW=14\text{ J}W=14 J and charge q=2 Cq=2\text{ C}q=2 C. So,

V=142=7 VV=\frac{14}{2}=7\text{ V}V=214​=7 V